Assuming that the population is normally distributed, construct a 90 % confidenc

Question

Assuming that the population is normally distributed, construct a 90 % confidence interval for the population mean, based on the following sample size of n7 1, 2, 3, 4, 5, 6 and 25 In the given data, replace the value 25 with 7 and recalculate the confidence interval. Using these results, describe the effect of an outlier (that is, an extreme value) on the confidence interval, in general. Find a 90% confidence interval for the population mean, using the formula or technology (Round to two decimal places as needed.)

Explanation / Answer

Ans:

when data is:

1,2,3,4,5,6,25

sample mean=6.57

sample standard deviation=8.304

n=7

df=7-1=6

critical t value=tinv(0.1,6)=1.943

90% confidence interval for population mean

=6.57+/-1.943*(8.304/sqrt(7))

=6.57+/-6.10

=(0.47, 12.67)

Now,when data is:

1,2,3,4,5,6,7

sample mean=4

sample standard deviation=2.160

90% confidence interval for population mean

=4+/-1.943*(8.304/sqrt(7))

=4+/-1.59

=(2.41, 5.59)

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