Create a BYTE array with the label ‘input’. This array may be of any length betw

Question

Create a BYTE array with the label ‘input’. This array may be of any length between 2 and 100.

Create a BYTE array with the label ‘output’. This array should be the same length as ‘input’.

Create a DWORD variable with the label ‘shift’. ‘shift’ should hold a single value. The value of ‘shift’ must be less than the length of ‘input’.

The program should then read each of the values from the array ‘input’ and place the values into the ‘output’ array but the location should be shifted by the amount in the ‘shift’ variable. If the shift would cause a value to be outside of the bounds of ‘output’, then the values should “wrap around” to the front of ‘output’.

For example:

My ‘input’ array is 5,0A,3,6,0C

‘shift’ is 3

The proper solution for ‘output’ is 3,6,0C,5,0A

Explanation / Answer

Label[] labels = new Label[10]; labels[0] = new Label(); labels[0].Text = "blablabla"; labels[0].Location = new System.Drawing.Point(100, 100); ... labels[9] = new Label(); Label[] _Labels = new Label[3]; private void MyForm_Load(object sender, EventArgs e) { _Labels[0] = this.Label1; _Labels[1] = this.Label2; _Labels[2] = this.Label3; } Label[ , ] _arr = new Label[4 , 4]; private void Form1_Load(object sender, EventArgs e) { for(int i=0;i

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