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ID: 361255 • Letter: C

Question

CLS mePredecessors recle 15 lO DE Ths exert, se only.cont ains. Partslo, ca, e ' aed k.· b Given the demand the cycle hne er tme pred.schon of Hhe New train set Seconds (round to-one decimal place). " ^ .)Tine theoretical minimum nombes of worKstations 1 /laod up. to next whole number) e)The total idle time per cycle for tha processSc enter response as a whole number The clAciency a the assembly line with with 5 = 1 1 Seconds lubrrSta tions= % entage rooded to IF one used lo workstations instead of 5, the as a percentage, roonded to onedeco al place). enter as a peru one decimal place senter S a Dercentage round -

Explanation / Answer

Demand for the product = 4500 units

Available time = 40 hour = 144000 seconds

Therefore , cycle time = Available time / Demand for the product = 144000/4500 = 32 seconds

CYCLE TIEM FOR PRODUCTION OF THE NEW TRAIN SET = 37 SECONDS

The Precedence diagram as follows :

                                                                                    A

            B

                              C

                   D

                                                       E

                                                                                  F

         

Total duration of all tasks A to F = 22 + 28 + 15 + 14 + 10 + 28 seconds = 117 seconds

The theoretical minimum number of workstations

= Total duration of all tasks / Cycle time

= 117/ 37

= 3.162 ( 4 rounded to next higher whole number )

THEORETICAL MINIMUM NUMBER OF WORKSTAIONS = 4

The workstationwise balancing of tasks as follows :

Workstation

Tasks

Total duration ( sec)

Idle time = Cycle time of 37 seconds – Total duration

1

A, C

22 + 15 = 37

                   0

2

B

28

                   9

3

D, E

14

                  23

4

E

10

                  27

F

28

                     9

Thus ,

Total idle time per cycle of the process is = 0 + 9 + 23 + 27 + 9 = 68 seconds

Efficiency of the assembly line with 5 workstations

= Total duration of al tasks / ( 5 workstations x Cycle time ) x 100

= 68 / ( 5 x 37 ) x 100

= 68 /185 x 100

= 36.75 %

Efficiency of the assembly line with 6 workstations

= Total duration of all tasks / ( 6 workstations x Cycle time ) x 100

= 68 / ( 6 x 37) x 100

= 30.63 %

TOTAL IDLE TIME PER CYCLE OF THE PROCESS = 68 SECONDS

EFFICIENCY OF THE ASSEMBLY LINE WITH 5 WORKSTATIONS = 36.75 %

EFFICIENCY OF THE ASSEMBLY LINE WITH 6 WORKSTATIONS = 30.63 %

CYCLE TIEM FOR PRODUCTION OF THE NEW TRAIN SET = 37 SECONDS