I need to simplify this equation using BooleanAlgebra. C1 = A1\' A0\' B1 B0\' +

Question

I need to simplify this equation using BooleanAlgebra. C1 = A1' A0' B1 B0' + A1' A0' B1 B0 + A1' A0 B1 B0' +A1' A0 B1 B0 + A1 A0' B1' B0' + A1 A0' B1' B0 + A1 A0' B1 B0 ' + A1A0' B1 B0 + A1 A0 B1' B0' + A1 A0 B1' B0 + A1 A0 B1 B0' + A1 A0 B1B0 Thanks for your help I need to simplify this equation using BooleanAlgebra. C1 = A1' A0' B1 B0' + A1' A0' B1 B0 + A1' A0 B1 B0' +A1' A0 B1 B0 + A1 A0' B1' B0' + A1 A0' B1' B0 + A1 A0' B1 B0 ' + A1A0' B1 B0 + A1 A0 B1' B0' + A1 A0 B1' B0 + A1 A0 B1 B0' + A1 A0 B1B0 Thanks for your help

Explanation / Answer

C1 = A1' A0' B1 B0' + A1' A0' B1 B0 + A1' A0 B1 B0' + A1' A0B1 B0 + A1 A0' B1' B0' + A1 A0' B1' B0 + A1 A0' B1 B0 ' + A1 A0' B1B0 + A1 A0 B1' B0' + A1 A0 B1' B0 + A1 A0 B1 B0' + A1 A0 B1 B0 = A1'A0'B1 + A1'A0B1 + A1A0'B1' + A1 A0' B1 B0 + A1 A0 B1' +A1 A0 B1 = A1' B1 + A1 B1' + A1 A0' B1 B0 + A1 A0 B1 = A1' B1 + A1 B1' + [A1 B1 (A0' B0 +A0)]

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