In a carnival booth, you win a stuffed giraffe if you toss a quarter into a smal

Question

In a carnival booth, you win a stuffed giraffe if you toss a quarter into a small dish. The dish is on a shelf above the point where the quarter leaves your hand and is a horizontal distance of 2.1 from this point (the figure ). If you toss the coin with a velocity of 6.4 at an angle of 60 above the horizontal, the coin lands in the dish. You can ignore air resistance.

part A) What is the height of the shelf above the point where the quarter leaves your hand?

part B) What is the vertical component of the velocity of the quarter just before it lands in the dish?

Explanation / Answer

x=vcos(60)*t vcos(60)= 6.4/2 = 3.2m/s x= 2.1m t=2.1/3.2=.65625s vy = vsin(60) - g*t = 6.4*v3/2 - 9.81*.65625 = 5.54-6.44 = -0.9 m/s ----- (1) height= v*t*sin(60) - .5*g*t2 = 1.53m above the point where the quarter left the hand ---------(2)

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