Please use Python to solve it. Thanks! A common kind of puzzle question is \"how
ID: 3675976 • Letter: P
Question
Please use Python to solve it. Thanks!
A common kind of puzzle question is "how many numbers between 1 and 1000 contain the digit 11". Write a function countNumsfithDigit(upperNumber, digit) that returns the number of numbers from 1 through upperNumber that contain the given digit. For example countNumsfithDigit(10, 9) should return 1, countNumsfithDigit(10, 1) should return 2, and countNumsfithDigit(30, 2) should return 12. Your function must use a list comprehension (but remember, it returns a number not a list!) and have only one line of code (in addition to the def line).Explanation / Answer
def count(unum,digit):
result = 0;
for i in range (1,unum):
result += has(x,digit)? 1 : 0;
return result
def has(x,digit):
while (x != 0)
if (x%10 == digit)
return true;
x = x /10;
return false;
def main():
unum = input('Choose a upper number')
digit = input('Choose a digit')
print "Count of numbers from 1 to " + unum + " that have 4 as a a digit is "+ count(unum,digit);
return 0;