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Pipeline questions Consider the memory location 0x 10000000 has the value 000000

ID: 3707937 • Letter: P

Question

Pipeline questions

Consider the memory location 0x 10000000 has the value 00000014 Sa3 holds the address 0x10000000 and $t1 holds the value 5 Consider the following MIPS code sequence with a 5-stage pipeline without data forwarding: addi Stl, Stl, 2 lw Stl, 0(Sa3) addi $t2, $t1, 5 addi Stl, Stl, 12 What are the contents of the registers St1, St2 and $a3 after the code sequence above is executed? Consider initial values of registers St1 St2 St3 Given below is a sequence of MIPS instructions with a 5-stage pipeline without data forwarding: Loop: sll St2, $t2,1 addi St2, St2, 1 bne Stl, St3, Loop addi Stl, Stl, 1 What are the contents of the registers St1, St2 and St3 after the code sequence is executed?

Explanation / Answer

Answer is as follows :

According to Chegg Guidelines, We are allowed to solve only first part of the question, So please repost others.

So now we have

$t1 = 5

$a3 at memory location whcih stores 00000014 in hexadecimal for which decimal equivalent is 00000020 in decimal.

So for given instructions :

a) addi $t1, $t1, 2

The instruction immediately add the 2 with contents of $t1 and store thee result back to $t1.

So $t1 = $t1 + 2

$t1 = 5 + 2 = 7

So upto know $t1 contains 7.

b) lw $t1,0($a3)

it loads the contents of 0 + $a3 to regiter $t1.

We have data 20 in $a3.

So after adding 0+20 = 20 i.e. store in $t1.

So upto know $t1 contains 20

c) addi $t2, $t1, 5

it add the contents of $t1 with 5 and store the result to register $t2.

$t2 = $t1 + 5

$t2 = 20 + 5 = 25

So upto know

$t1 contains 20

$t2 contains 25

d) addi $t1, $t1, 12

It add the contents of $t1 with 12 and store them back to $t1.

So

$t1 = $t1 + 12

$t1 = 20 + 12 = 32

So $t1 contains 32.

So the final contents are :

$t1 = 32

$t2 = 25

$a3 = 20

All the data are in decimal.

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