I need number 8 answer please ASAP. Fldting Point Quiz B Answer all questions. F
ID: 3747457 • Letter: I
Question
I need number 8 answer please
ASAP. Fldting Point Quiz B Answer all questions. February 16, 2018 section time: For all of these questions, "floating point" will refer to IEEE standard representati 1. Approximately how many significant digits are contained in double precision floating point? 15 c) 24 double precision floating point number is approximately c) 1023 2. The 53 a) 10 d)106 3. The smallest positive single precision floating point number is: a) 2-150 149 c) 2-102 d) 2-1023 4. The single precision floating point 1111111 00000000110000000000000 represents: a)0 b) infinity a number S. The hidden bit can be hardwired by: aOR the exponent bits NOR the exponent bits b) AND the exponent bits c) NAND the exponent bits 6. Including the hidden bit, how many significant bits are there in single precision floating point representation? a) 23 b)24 c)52 d)53 7. Which of the following is/are trueabout using "denormalized" form? L Every number has a unique representation The gap around 0 is consistent It allows numerical solutions to have greater accuracy · III. a)land 11 b)I and III c) II and III d) all of the above 8. Most programmers prefer to use double precision instead of single precision because a) the range of single precision is not sufficient for most problems b) the number of significant bits/digits in single precision is not sufficient c) both of the above enone of the above d) neither of the above 9. Floating Point Arithmetic preserves all of the properties of real numbers a) TRUE FALSE 10. To set the zero flag for a Signed Integer type variable, a) XOR all 32 bits c) NOR all 32 bits b) XOR the 31 least significant bits OR the 31 least significant bits
Explanation / Answer
Answer: Option C
Single precision: it uses 8-bits for exponential part, means it can represent minimum value as 2^-(2^7) and as large value as 2^(2^7).
Double precision: It uses 11-bits for exponent, so it can range from 2^-(2^10) to 2^(2^10).