Please help ASAP with explanation please 2\'s complement arithmetic is not close

Question

Please help ASAP with explanation please

2's complement arithmetic is not closed on negation.in the other words, there exists a value x such that -x is not representable because it goes out of range. for 4-bit 2's complement, what is x?

the second question is multible choise: which on of 5 choise is correct:

2-which of the following does not describe an instruction in the MIPS ISA as discussed in this course

1- load 32-bit word from memory into a register

2- store a 32-bit word from a register into memory

3- jump to a function saving the return address in a register

4- replace two 32-bit values from top of a stack stored in memory with their sum

5- place a 16- bit immediate value in the top 16 bits of a register and zero the bottom 16 bits

Explanation / Answer

1)

In signed magnitude +0 can be represented using 4 bits 0000 and -0 can be represented in 1000.

-0 cannot be represented in 2’s complement because it goes out of the range of 4 bits because:

Consider 0-0000

1’s complement of 0 is 1111

And 2‘s complement of 0 will be as follows:

  1111

    1111

    +    1

10000

The result is 5 bit binary number.

Therefore, the value of x will be 0.

2)option 5

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects