Division is to be done using the algorithm in the text. The size of the quotient
ID: 3785326 • Letter: D
Question
Division is to be done using the algorithm in the text. The size of the quotient is 8 bits. Which of the following is NOT true? There are 9 iterations of the loop The remainder is 16 bits wide. The divisor is 16 bits wide. The initial remainder value is 0. What are the values in hi and lo after the following? addi $t0, $0, 2 addi $t1, $0, 7 mult $t1, $t0 Io = 0x0000000E hi = 0x00000000 Io = 0x00000000 hi = 0x00000002 Io 0x0000000 hi 0xFFFFFFFF Io = 0x00000002 hi = 0x00000000 The number -1.0 is to be stored in single precision using the IEEE standard. What is the value of the exponent? 00000000 1 10000000 01111111Explanation / Answer
1) option d is not true y because if in the intial remainder itself if we get 0 then the quotient can't be 8 bits which has mentioned in the question
2) option "B"
Because in to contains 2
t1 contains 7 then multiplication of these two 14 which Rpresented as E in hexadecimal. So this value exists in lo and 0 in hi
3)option D
Which is 128 with base 2 as binary indication