The mutation leading to low frequency hearing loss in Family B is a nucleotide s
ID: 38116 • Letter: T
Question
The mutation leading to low frequency hearing loss in Family B is a nucleotide substitution that changes the location where an intron is removed and two exons are spliced together. As a result, 4 bases are inserted. The wild-type DNA sequence and the mutant DNA sequence are given below. CAPITAL letters indicate exon sequence and lower case letters indicate intron sequence. Wild-type 5'-CCC CGT CAA Ggtaagtaa?..cagaatctctcgtcttctcttgcagCC AAC AGG AAG GCC GGG TGT GCA GTC ACA TCT CTG CTA GCT TCG GAG CTG ACC AAG GAT GAT GCC ATG GCT GCT GTT CCT GCC AAG GTG TCC AAG AAC AGT GAG ACA TTC CCC ACA ATC CTT GAG GAA GCC AAG GAG TTG GTT GGC CGT GCA AGC TAA-3' Mutant 5'-CCC CGT CAA GTT AAgtaa?cagaatctctcgtcttctcttgcagC CAA CAG GAA GGC CGG GTG TGC AGT CAC ATC TCT GCT AGC TTC GGA GCT GAC CAA GGA TGA TGC CAT GGC TGC TGT TCC TGC CAA GGT GTC CAA GAA CAG TGA GAC ATT CCC CAC AAT CCT TGA GGA AGC CAA GGA GTT GGT TGG CCG TGC AAG CTA A-3' 15. Using this DNA sequence information, write the mRNA sequence, then use the codon table in your textbook to figure out the amino acid sequence coded for by each DNA sequence. Be sure to indicate all STOP codons. Remember that an AUG codon in the middle of an mRNA transcript is NOT a new start codon, but codes for the amino acid methionine.Explanation / Answer
Uaa, uga, uag sTOP codons
Att, act, atc complimentart DNA bases
67-14 = 53 wild type , stop codon ATC, row 3 on the right
67-45 =. 22. Mutant aa, stop codon ATC row 2 on the left
A difference of 31 amino acid