Need help with a Java problem: Copy the program class provided below called Fina

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Need help with a Java problem:

Copy the program class provided below called FinalAnswer. This contains only a main method. You are to add your method to that program class. When you compile and run it, the main method will call the method you are writing in response to the problem below.

FinalAnswer.java:

import java.util.ArrayList;
import java.util.Arrays;
import algs13.Stack;
import stdlib.*;

public class FinalAnswer {

   // Your methods go here.

   public static void main(String[] args) {
       StdOut.println(floorlog(32));
       StdOut.println(floorlog(35));
       StdOut.println(floorlog(64));
       StdOut.println(floorlog(2048));

       Double[] sqarray = {3.5, 4.7, 10.1, 25.0, 76.34, 100.01, 256.0};
       ArrayList<Double> dlist = new ArrayList<Double>(Arrays.asList(sqarray));
       StdOut.println(dlist);
       squareRootList(dlist);
       StdOut.println(dlist);

       StdOut.println(falling(10, 2));
       StdOut.println(falling(52, 6));

       dlist = new ArrayList<Double>();
       StdOut.println(sumBelowLimit(dlist, 50.0));
       Double[] sbarray = {45.3, 12.4, 50.1, 32.8, 75.5, 49.9, 50.0};
       dlist = new ArrayList<Double>(Arrays.asList(sbarray));
       StdOut.println(sumBelowLimit(dlist, 50.0));

       ArrayList<Integer> ilist = new ArrayList<Integer>();
       StdOut.println(productOfEvens(ilist));

       Integer[] eparray1 = {2, 3, 4, 9, 11, 12};
       ilist = new ArrayList<Integer>(Arrays.asList(eparray1));
       StdOut.println(productOfEvens(ilist));

       Integer[] eparray2 = {7, 3, 53, 9, 11, 19};
       ilist = new ArrayList<Integer>(Arrays.asList(eparray2));
       StdOut.println(productOfEvens(ilist));

       String[] starray = {"hello", "how", "are", "you"};
       reverse(starray);
       StdOut.println(Arrays.toString(starray));
   }
}

Write a recursive public static method to calculate the falling power function. It has the signature: public static long falling (long n long e) As you can see, it takes two long parameters n and e. ere is the mathematical definition ne n (n-1)ei ne n the expressions above, the notation ng is read "n to the falling power e"

Explanation / Answer

import java.util.ArrayList;
import java.util.Arrays;
import algs13.Stack;
import stdlib.*;
public class FinalAnswer {
public static long   falling(long n, long e)
{
   if (e==0)
       return(1);
   else
   {
       return n* falling((n-1),(e-1))
   }
}
public static void main(String[] args) {
StdOut.println(floorlog(32));
StdOut.println(floorlog(35));
StdOut.println(floorlog(64));
StdOut.println(floorlog(2048));
Double[] sqarray = {3.5, 4.7, 10.1, 25.0, 76.34, 100.01, 256.0};
ArrayList<Double> dlist = new ArrayList<Double>(Arrays.asList(sqarray));
StdOut.println(dlist);
squareRootList(dlist);
StdOut.println(dlist);
StdOut.println(falling(10, 2));
StdOut.println(falling(52, 6));
dlist = new ArrayList<Double>();
StdOut.println(sumBelowLimit(dlist, 50.0));
Double[] sbarray = {45.3, 12.4, 50.1, 32.8, 75.5, 49.9, 50.0};
dlist = new ArrayList<Double>(Arrays.asList(sbarray));
StdOut.println(sumBelowLimit(dlist, 50.0));
ArrayList<Integer> ilist = new ArrayList<Integer>();
StdOut.println(productOfEvens(ilist));
Integer[] eparray1 = {2, 3, 4, 9, 11, 12};
ilist = new ArrayList<Integer>(Arrays.asList(eparray1));
StdOut.println(productOfEvens(ilist));
Integer[] eparray2 = {7, 3, 53, 9, 11, 19};
ilist = new ArrayList<Integer>(Arrays.asList(eparray2));
StdOut.println(productOfEvens(ilist));
String[] starray = {"hello", "how", "are", "you"};
reverse(starray);
StdOut.println(Arrays.toString(starray));
}
}

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