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Please write your own source code and make sure the code compiles. C++ Programmi

ID: 3838342 • Letter: P

Question

Please write your own source code and make sure the code compiles. C++ Programming. Quadratic Root Tool. QuadraticRootTool.cpp
The roots of a quadratic equation in the form a x^2 + b x + c = 0 can be obtained using these formulas:

b^2?4ac is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots; if it is zero, the equation has one root. If it is negative, the equation has no real roots.

Write a program that prompts the user to enter values for a, b, and c and displays the result based on the discriminant. If the discriminant is positive, display two roots. If the discriminant is 0, display one root. Otherwise, display "The equation has no real roots."

Note that you can use sqrt(x) (#include ) to compute square root of x.

Here are some sample runs; please match this output format EXACTLY (matching at least 4 decimal places). This means the output must list r1 (the “positive” root) first if there are two roots:

Here is a sample run:

Enter a, b, c: 1.0 3 1

The equation has two roots: -0.38166 and -2.61803

Enter a, b, c: 1 2.0 1

The equation has one root: -1

Enter a, b, c: 1 2 3

The equation has no real roots.

The roots of a quadratic equation in the form a x^2 + b x + c = 0 can be obtained using these formulas: x = -b plusminus Squareroot b^2 - 4ac/2a b^2?4ac is called the discriminant of the quadratic equation. If it is positive, the equation has two real roots; if it is zero, the equation has one root. If it is negative, the equation has no real roots.

Explanation / Answer

#include<bits/stdc++.h>
using namespace std;

int main() {
   float a,b,c;
   cout<<"Enter a,b,c :"<<endl;
   cin>>a>>b>>c;
   int d;
   float r1,r2;
   d = b*b-4*a*c;
   if(d<0){
       cout<<"The equation has no real roots."<<endl;
   }
   else if(d == 0){
       r1 = (-b)/2*a;
       cout<<"The equation has one root: "<<r1<<endl;
   }
   else{
       r1 = (-b+sqrt(d))/2*a;
       r2 = (-b-sqrt(d))/2*a;
       cout<<"The equation has two roots:" <<r1<<" and "<<r2;
   }
   return 0;
}