If two computers are connected by hub using fast ethernet. d = 512 m and c = 3*1

Question

If two computers are connected by hub using fast ethernet. d = 512 m and c = 3*10^8 m/s i) fibd the minimum frame size? ii) if switch is used; theoritically, is there any limitation for frame size and why ? If two computers are connected by hub using fast ethernet. d = 512 m and c = 3*10^8 m/s i) fibd the minimum frame size? ii) if switch is used; theoritically, is there any limitation for frame size and why ? i) fibd the minimum frame size? ii) if switch is used; theoritically, is there any limitation for frame size and why ?

Explanation / Answer

If two computers are connected by hub using fast ethernet.

d = 512 m and c = 3*10^8 m/s

i)

t=d/c = 512 m / 3*10^8 m/s = 1706.66*10^-9 sec

Now hub using fast ethernet has 100Mbps speed then

minimum frame size = 100Mbps * 1706.66*10^-9 sec = 170.666 bits or 170 bits

ii)

If switch is used then speed will be 10/100 Mbps or 1 Gbps

So frame size will be 17/170 or 1706 bits.

Difference comes because of speed and switches operate at Layer 2 of the OSI model and Hubs are classified as Layer 1 devices per the OSI model.

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