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Could you please solve this C++ question without using void & string functions &

ID: 3841423 • Letter: C

Question

Could you please solve this C++ question without using void & string functions & only and only by using if else, while, for?

This C++ problem related to the previous one, and please somebody solve it without using void and string fuctions, and only and only by using if else, while, for

A palindrome is a number or a text phrase that reads the same backward as forward. For example, each of the following five-digit integers is a palindrome: 12321 e 55555 45554 11611 e Write a program that reads in a five-digit integer and determines whether it's a palindrome. The sample output is provided below. Hint: Use the division and modulus operators to separate the number into its individual digits. Enter a five-digit integer 1 to quit): 12 The number 12321 is a palindrome Enter a five-digit integer (or 1 to quit): 12345 The number 12345 is not a palindrome. Enter a five-digit integer (or 1 to quit): 123 The number 123 is not a five-digit number. Enter a five-digit integer (or 1 to quit): -1 Good bye!

Explanation / Answer

The two programs are as follows:
The first one is for the five digit number:
#include<iostream.h>

int main(){
int input; //holds the input number
int rev = 0; // holds the reverse number
int num; //holds the input number for calculation

cout << "Enter a five-digit integer (or -1 to quit)";
cin >> input;
if (input == -1){
     cout << "Good bye!";
     return;
}

num = input;
while (num != 0){
     rem = num % 10;
     rev = rev*10 + rem;     //In this while loop reverse number is getting build up
     num = num / 10;
}
if (rev == input)
     cout << "The number " << input << "is a palindrome!" << endl;
else
     cout << "The number " << input << "is not a palindrome." << endl;

return 0;
}

The second program is as follows:

#include<iostream.h>

using namespace std;

int main(){
char input[256]; //holds the input string. Assuming it takes 256 characters.
char rev[256]; // holds the reverse string
char temp[256] //holds the input string without spaces
int found;

int statement;   // holds whether input is a word or statement. For word it is 0 and for statement it is 1

cout << "Enter a string (or -1 to quit)";
cin.getline(input,256);
if (input[0] == '-' && input[1] == '1'){
     cout << "Good bye!";
     return 0;
}
statement = 0;
count = 0;
for (int i = 0; input[i] != ' '; i++){
      count++;
      if (input[i] != ' ')
         temp[i] = input[i];   //building a string without spaces
      else
         statement = 1;
}

for (int i = count-1; i > 0; i--){
      rev[count-1-i] = temp[i]; //building a reverse string

found = 1 //Assume it is a palidrome

for (int i = 0; i<count; i++){
     if (rev[i] != temp[i]){
         found = 0;
         break;
     }
        
}
if (found == 1){
     if (statement == 1)
        cout << "The statement " << temp << "is a palindrome!" << endl;
     else
        cout << "The word " << temp << "is a palindrome!" << endl;
}
else {
     if (statement == 1)
        cout << "The statement " << temp << "is not a palindrome." << endl;
     else
        cout << "The word " << temp << "is not a palindrome." << endl;
}
return 0;
}