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Topology Subnet A Subnet B Go/o FO/6 PC-B R1 FO/5 S1 Objectives Part 1: Develop

ID: 3884691 • Letter: T

Question

Topology Subnet A Subnet B Go/o FO/6 PC-B R1 FO/5 S1 Objectives Part 1: Develop the IPv4 Address Scheme Part 2: Cable topology and Initialize and Reload Devices Part 3: Configure Device IPv4 and Security Settings Part 4: Test and Verify IPv4 End-to-End Connectivity Part 5: Configure IPv6 Addressing on R1 Part 6: Test and Verify IPv6 End-to-End Connectivity Part 7: Use the IOS CLI to Gather Device Information Part 8: Save the R1 Configuration to a TFTP Server Scenario In this practice you will configure the devices in a small network. You must configure a router, switch and PCs to support both IPv4 and IPv6 connectivity. You will configure security, including SSH, on the router. You will test and document the network using common CLI commands. Finally, you will save the router configuration to a TFTP server Part 1: Develop the IPv4 Addressing Scheme Time: 25 minutes Given an IP address and mask of 192.168.30.0/24 design an IP addressing scheme that satisfies the following requirements. Use VLSM to avoid wasting host addresses. Number of Hosts 40 12 Subnet Subnet A Subnet B No subnet calculators may be used in the final exam, so try and avoid using one for this practice. Host computers will use the first IP address in the subnet. The network router will use the LAST network host address. The switch will use the second to the last network host address. © 2013 Cisco andor its anates Al rights reserved This document is Cisco Public Page 1 of S

Explanation / Answer

PART 1 :-

Subnet A
number of bits in the subnet mask = 26
new ip mask =255.255.255.192
new subnet mask(decimal)= /26
maximum number of subnets= 4
nubmer of usable host per subnet =62
ip subnet address = 192.168.30.1
last ip host address = 192.168.30.62

Subnet B
number of bits in the subnet mask = 28
new ip mask =255.255.255.240
new subnet mask(decimal)= /28
maximum number of subnets= 16
nubmer of usable host per subnet =14
ip subnet address = 192.168.30.64
last ip host address = 192.168.30.78

PC-A 192.168.30.1 255.255.255.192
R1-G0/0 192.168.30.62 255.255.255.192
R1-G0/1 192.168.30.64 255.255.255.240
s1 NA NA
PC-B 192.168.30.78 255.255.255.240

PART 2 :-

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