I have these problems that I cannot get right for the life of me. Please help! 1
ID: 3893692 • Letter: I
Question
I have these problems that I cannot get right for the life of me. Please help!
1.You are tasked with designing a roller coaster loop-the-loop with radius r. How fast must the cart move at the top of the loop (when upside down), such that the normal force acting on the riders vanishes?
(Practise to derive the answer by first drawing a free-body diagram and then applying Newton's 2nd Law.)
2.You are tasked with designing a roller coaster loop-the-loop with radius r. How fast must the cart move at the top of the loop (when upside down), such that the normal force acting on the riders is half their weight?
(Practise to derive the answer by first drawing a free-body diagram and then applying Newton's 2nd Law.)
3. You are tasked with designing a roller coaster loop-the-loop with radius r. How fast must the cart move at the top of the loop (when upside down), such that the normal force acting on the riders is equal to their weight?
(Practise to derive the answer by first drawing a free-body diagram and then applying Newton's 2nd Law.)
4. You are tasked with designing a roller coaster loop-the-loop with radius r. If the cart has just the required minimum speed (no normal force) at the top of the loop (when upside down), what is the carts speed at the bottom of the loop?
5. Consider a circular roller coaster loop of radius 11.2 m. Draw a freebody diagram for the roller coaster car at the top of the loop. Then find the speed at which the car must move, such that the normal force acting on the car vanishes.
6. Consider a circular roller coaster loop of radius 15.1 m. You already know that if the car starts from a height of 2.5 r at rest, the normal force acting on the car at the top will vanish.
Now assume the car starts from a level track, a height of 15.1 m above the ground. The track first guides the car to ground level and then into the loop. At which initial speed must the car move on the elevated track (height 15.1 m) such that it still has the required speed at the top of the loop for the normal force to vanish?
Explanation / Answer
Draw a free body diagram: Normal force is the force against the tracks, and normal force when upside down would be the force upward. If the cart is in constant velocity, no acceleration you can assume its in static equilibrium. So the Normal force (force up)= weight x9.8m/s (force down). I cannot see the diagram so do not know how R would play into this problem or if there is a v or a value in the diagram