In the winter Olympics, after all games American and Russian hockey teams decide
ID: 3894286 • Letter: I
Question
In the winter Olympics, after all games American and Russian hockey teams decided to play a fun
farewell hockey game
In the winter Olympics, after all games American and Russian hockey teams decided to play a fun farewell hockey game. A special hockey puck of mass m was designed with very small amount of explosive inside it that would activate shortly after a precise amount of impulse is imparted to puck by the club. Finally a Russian player hits the puck with right force while he was shooting the puck from a distance d directly towards the center of the goal. Let the initial speed of the puck be vo. The puck explodes into two fragments exactly halfway to the goal. One piece of mass m1 = 0.6m slides backward (not directly) with a speed towards the player and passes a point that is to the side of the spot it was initially shot from. See the figure. The other piece of the puck m2 = 0.4m continues on towards the goal with a speed . The second piece will hit the goal but distance v to right of the center. Assume that there is no friction as the puck slides along the ice and mass of explosive can be ignored. In terms of d Calculate y.Explanation / Answer
0.4m*V2f*cos(theta2) = 0.6m*V1f*cos(theta1)
0.4m*V2f*cos(theta2) = 0.6m*V1f*cos(tan inverse 6/8)
cos (theta2) = 1.2*(V1f/V2f)
also 0.4m*V2f*sintheta2 = 0.6m*v1f*sin36.86
sintheta2 = 0.885*(V1f/V2f)
squaring and adding
(V1f/V2f) = 0.67
hence costheta 2 = 1.2*.67
theta 2= 36.48
2y/d = tan36.48
y = .37d