In the circuit shown, we know the current through resistor R1 to I1 = 6A in the

Question

In the circuit shown, we know the current through resistor R1 to I1 = 6A in the direction shown.

In the circuit shown we know the current through resistor R1 to be = 6A in the direction shown. Write down the loop equation for loop abfliga, travel the loop clockwise. Find the value of I4. Write down the node equation at junction h. Find the value of I3. Write down the loop equation for loop bcdlib. Travel clockwise. Find the value of I2. Determine I and Is. Calculate the potential difference Calculate the power delivered by the battery and the total power dissipated in the resistors.

Explanation / Answer

a)

14 - 6*1 - I4 * 2 = 0

8 = I4*2

I4 = 8/2 = 4 A

b)

I3 + I4 = 6

I3 = 6 - I4 = 6 - 4 = 2 A

c)

-2*I2 + 2*1 +6*1 = 0

8 = 2*I2

I2 = 8/2 = 4 A

d)

4*2 -2*1-I5*1 = 0

I5 = 6 A

I = I4 + I5 = 4 + 6 = 10 A

e)

Va - 2*4 - Vd = 0

Va - Vd = 8

Vad = 8V

f)

Power delivered by battery = V*I = 14*10 = 140 W

Total Power delivered = 6^2 * 1 + 4^2 * 2 + 2^2 * 1 + 4^2 * 2 + 6^2 * 1 = 140 W

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