Please help! The Mass Particle Spectrometer shown here consists of a uniform mag

Question

Please help!

The Mass Particle Spectrometer shown here consists of a uniform magnetic field |B| = 1.25 T either into or out of the page, in the region of the shaded box. Particles # 1 through # 3 all have charge magnitude |q| = 1.6 times 10 - 19 C. They enter with the same initial velocity v = 6 times 105 m/s and follow the trajectories shown. Which particle is the most massive? The mass of particle #3 is determined to be 1.67 times 10-27 kg. Calculate the distance L labeled on the diagram. L = 2.5 times 10-3 m L = 5.0 times 10-3 m L = 6.0 times 10-3 m L = 7.5 times 10-3 m L = 10.0 times 10-3 m What is the magnitude of the force on particle #3 when it is at the point marked a (the top of its trajectory)? F = 1.5 times 10-14 N F = 3.0 times 10-14 N F = 6.0 times 10-14 N F = 1.2 times 10-13 N F = 2.4 times 10-13 N

Explanation / Answer

32)   We know that  

   radius in a magnetic field = mv / Bq

here v , B and q are constant in the given question .

so more the mass of particle more the radius .

from the given diagram , it is clear that particle 3 has more radius

So particle 3 has more mass

   so the answer is option   C

33)   the diameter is given by 2L   for particle 3

so radius = L

radius L = mv/Bq

L = 1.67 x 10-27 x 6 x 105 / 1.25 x 1.6 x 10-19

L = 5.01 x 10-3 M

so the answer is option B

34)   force = qvB

   force = 1.6 x 10-19 x 6 x 105 x 1.25

force = 12 x 10-14

force = 1.2 x 10-13 N

so the answer is option D

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---