In ( Figure 1 ) , the moving rod has a resistance of 0.25 ? and moves on rails 2
ID: 3900678 • Letter: I
Question
In (Figure 1) , the moving rod has a resistance of 0.25 ?and moves on rails 20.0?cm apart. The stationaryU-shaped conductor has negligible resistance. When a force of 0.410N is applied to the rod, it moves to the right at a constant speed of 1.30m/s . In (Figure 1) , the moving rod has a resistance of 0.25 ?and moves on rails 20.0?cm apart. The stationaryU-shaped conductor has negligible resistance. When a force of 0.410N is applied to the rod, it moves to the right at a constant speed of 1.30m/s . In (Figure 1) , the moving rod has a resistance of 0.25 ?and moves on rails 20.0?cm apart. The stationaryU-shaped conductor has negligible resistance. When a force of 0.410N is applied to the rod, it moves to the right at a constant speed of 1.30m/s . In (Figure 1) , the moving rod has a resistance of 0.25 ?and moves on rails 20.0?cm apart. The stationaryU-shaped conductor has negligible resistance. When a force of 0.410N is applied to the rod, it moves to the right at a constant speed of 1.30m/s . Part A What is the magnetic field? Express your answer using two significant figures. B = T Provide FeedbackContinue Part A What is the magnetic field? Express your answer using two significant figures. B = T Part A What is the magnetic field? Express your answer using two significant figures. B = T Part A What is the magnetic field? Express your answer using two significant figures. B = T Part A What is the magnetic field? Express your answer using two significant figures. B = T Part A What is the magnetic field? Express your answer using two significant figures. B = T B = T B = T Provide FeedbackContinue Figure 1 of 1 In (Figure 1) , the moving rod has a resistance of 0.25 ?and moves on rails 20.0?cm apart. The stationaryU-shaped conductor has negligible resistance. When a force of 0.410N is applied to the rod, it moves to the right at a constant speed of 1.30m/s . Part A What is the magnetic field? Express your answer using two significant figures. B = T Provide FeedbackContinue Figure 1 of 1Explanation / Answer
F = (Bl)^2 * v / R
B = sqrt(F*R / v) / l
= sqrt (0.41 * 0.25 / 1.3) / 0.2
= 1.403 T