Max z 400x, +100x s.t. 8x, +10x, 80 2x, +6x2 36 x.x, 20 mal Obi. Value z-4000 Va

Question

Max z 400x, +100x s.t. 8x, +10x, 80 2x, +6x2 36 x.x, 20 mal Obi. Value z-4000 Variable Reduced Cost Value 10 C2 Constraint Slack and Surpls Dual Value 50 16 1E+30 320 100 RHS Value 80 400 Allowable 64 1E+30 Allowable 80 Constraint 36 1E-30 16 Use Computer Output 3. Suppose the right hand side of constraint 1 is decreased by 67. Which one of the following statements is guaranteed to be true? the z-value becomes 3950 the z-value becomes 7350 O the z-value becomes 650. o none of the answers are correct

Explanation / Answer

The 1st constraint will now become 8x1+10x2<=13

R.H.S. was earlier 80 and when it is reduced by 67 RHS will become 80-67 = 13.

When this change is introduced then the objective function (z) value can be determined using the solver function in excel:

Thus the answer is the 3rd option "the z-value becomes 650".

Variables as determined by solver x1 1.625 x2 0 Formula z 650 z = 400x1+100x2 Constraints 13 <= 13 8x1+10x2<=13 3.25 <= 36 2x1+6x2<=36

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