Cost-Duration trade-off: Fill in missing data regarding slope and maximum crash
ID: 460011 • Letter: C
Question
Cost-Duration trade-off:
Fill in missing data regarding slope and maximum crash time into the table below based on given information.
If you should reduce the duration of this project, which activity would you start with? Explain.
Activity ID
Slope
Maximum Crash Time
Direct costs
Normal
Crash
Time
Cost (USD)
Time
Cost (USD)
A
3
50
2
70
B
6
80
4
160
C
10
60
9
90
D
6
70
6
70
E
11
50
7
150
Activity ID
Slope
Maximum Crash Time
Direct costs
Normal
Crash
Time
Cost (USD)
Time
Cost (USD)
A
3
50
2
70
B
6
80
4
160
C
10
60
9
90
D
6
70
6
70
E
11
50
7
150
Explanation / Answer
Example slope for A=(70-50)/(3-2)=20
for B=(160-80)/(6-4)=40 and similarly for others
Activity ID Slope Max Crash Time Direct Cost Normal Crash Time Cost Time Cost A 20 1 3 50 2 70 B 40 2 6 80 4 160 C 30 1 10 60 9 90 D 0 0 6 70 6 70 E 25 4 11 50 7 150 Slope= (Crash cost-Normal Cost)/(Normal time- crash time) Max Crash time=Normal Time-Crash time Least slope is that of Activity A hence it will be crashed first with slope it means the increase in cost in per unit crashing time If we crash activity A first it will cost the least of all the activities