If your front lawn is 19.0ft wide and 20.0ft long, and each square foot of lawn
ID: 475387 • Letter: I
Question
If your front lawn is 19.0ft wide and 20.0ft long, and each square foot of lawn accumulates 1150 new snow flakes every minute, how much snow (in kilograms) accumulates on your lawn per hour? Assume an average snow flake has a mass of 1.80mg. (The answer should be in kg/h) If your front lawn is 19.0ft wide and 20.0ft long, and each square foot of lawn accumulates 1150 new snow flakes every minute, how much snow (in kilograms) accumulates on your lawn per hour? Assume an average snow flake has a mass of 1.80mg. (The answer should be in kg/h) If your front lawn is 19.0ft wide and 20.0ft long, and each square foot of lawn accumulates 1150 new snow flakes every minute, how much snow (in kilograms) accumulates on your lawn per hour? Assume an average snow flake has a mass of 1.80mg. (The answer should be in kg/h)Explanation / Answer
The lawn is 19.0 ft wide and 20.0 ft long.
Therefore, area of the lawn = (20.0 ft)*(19.0 ft) = 380 sq.ft
Each square foot the lawn accumulates 1150 new snowflakes every minute.
Therefore, number of snowflakes accumulated on the lawn in 1 hour = (380 sq.ft)*(60 min/hr)*(1150 /sq. ft/min) = 26220000/hr
The average mass of a snowflake is 1.80 mg; therefore, the mass of snow accumulated on the lawn in 1 hour = (1.80 mg)*(26220000/hr) = 47196000 mg = (47196000 mg/hr)*(1 g/1000 mg)*(1 kg/1000 g) = 47.196 kg/hr (ans).