I really need help with (e), have no idea how to explain it. Thank you! Normal h

Question

I really need help with (e), have no idea how to explain it.

Thank you!

Normal heptane is dehydrocyclicized to toluene and hydrogen in a continuous vapor-phase reaction: C_7 H_16 rightarrow C_6H_5CH_3 + 4H_2 Pure heptane at 400 degree C is fed to the reactor. The reactor operates isothermally at 400 degree C and the reaction goes to completion. Data: The average heat capacity of n-heptane between 25 degree C and 400 degree C is 0.2427 kJ/(mol middot degree C). Taking a basis of 1 mol of heptane fed, draw and label a flowchart. Taking elemental species [C(s), H_2(g)] at 25 degree C as references, prepare and fill in an inlet-outlet enthalpy table. (See Example 9.5-2.) Calculate the required heat transfer to or from the reactor (state which it is) in kJ. What is the heat of the heptane dehydrocyclization reaction (Delta H_t, ) at 400 degree C and 1 atm? The calculation of Part (c) would clearly have been much simpler if you had just looked up the heat of reaction at 400 degree C instead of calculating it after the fact. Briefly explain why you probably could not have done it that way.

Explanation / Answer

Ans:-e) In part c) we need to calculate the heat transfer using the formula.

Now in the given question it has been said the calculation prt in c) would clearly have been much simpler if we have just look at heat of reaction at 4000 C instead of calculating it but we could not do it because temperature is an intensive property so it does not depend on the amount of substance and there has to be a temperature difference which is called the driving force. A greater temperature difference will give a greater rate of heat transfer.

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