Please included a detailed answer. I know the answer to Part A is the first choi
ID: 488972 • Letter: P
Question
Please included a detailed answer. I know the answer to Part A is the first choice, but having problems with Part B (answer is second choice). I thought it would be the first choice because if the first step is rate determining that means it would be slow relative to the second step. Thanks!!
The reaction
2NO(g)+Cl2(g)2NOCl(g)
obeys the rate law, rate=k[NO]2[Cl2]. The following mechanism has been proposed for this reaction:
NO(g)+Cl2(g)NOCl2(g)
NOCl2(g)+NO(g)2NOCl(g)
Part A
What would the rate law be if the first step were rate determining?
Part B
Based on the observed rate law, what can we conclude about the relative rates of the two steps?
The reaction
2NO(g)+Cl2(g)2NOCl(g)
obeys the rate law, rate=k[NO]2[Cl2]. The following mechanism has been proposed for this reaction:
NO(g)+Cl2(g)NOCl2(g)
NOCl2(g)+NO(g)2NOCl(g)
Part A
What would the rate law be if the first step were rate determining?
rate=k[NO][Cl2] rate=k[NO]2[Cl2] rate=k[NO] rate=k[Cl2]Part B
Based on the observed rate law, what can we conclude about the relative rates of the two steps?
the first step must be slow relative to the second step the second step must be slow relative to the first step the first step must be equal to the second stepExplanation / Answer
part A ) your answer is correct .
Part B) correct answer : the first step must be slow relative to the second step
Explanation :
rate=k[NO]2[Cl2].
rate law depends on slow step process only.
here rate law expression NO and Cl2 are reactants.
so the first option is correct.