I just need to know how to find the % dissociation from a .5 M solution with the

Question

I just need to know how to find the % dissociation from a .5 M solution with the information I collected from the 2 dilutions. notebook, but be clear about which question you are answering. o copy the question into your l. Revisit Pre-Lab Question 3. Based on work done in this lab exercise, provide a critical evaluation of your predictions. Were your predictions c Use calculations to support your reasoning (for example, calculate the ociation for the 0.5 10x dilution, and 20x dilution for at least one of the acids).

Explanation / Answer

For 0.5 M HCl ,10 x dilution

pH=1.35

So [H+]=10-1.35=0.04

Now we have data 18.02 ml H2O and 2.01 ml HCl

So M1V1=M2V2

2.01*0.5=20.03*M2

So [HCl]=M2=0.05 after dilution

So dissociation=[H+]/[HCl]=0.04/0.05=0.8

Means 80% dissociation

(2) 20 x dilution

pH=1.70

So [H+]=10-1.7=0.02

Now we have data 19 ml H2O and 0.90 ml HCl

So M1V1=M2V2

0.90*0.5=19.90*M2

So [HCl]=M2=0.022 after dilution

So dissociation=[H+]/[HCl]=0.02/0.022=0.9090

Means 90.90% dissociation

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