Consider the reaction: CO( g )+H2O( g )CO2( g )+H2( g ) K c=102 at 500 K A react

Question

Consider the reaction:
CO(g)+H2O(g)CO2(g)+H2(g)
Kc=102 at 500 K
A reaction mixture initially contains 0.140 M COand 0.140 M H2O.

Part A

What will be the equilibrium concentration of [CO]?

Part B

What will be the equilibrium concentration of [H2O]?

Part C

What will be the equilibrium concentration of [CO2]?

Part D

What will be the equilibrium concentration of [H2]?

Consider the reaction:
CO(g)+H2O(g)CO2(g)+H2(g)
Kc=102 at 500 K
A reaction mixture initially contains 0.140 M COand 0.140 M H2O.

Part A

What will be the equilibrium concentration of [CO]?

[CO] =   M  

Part B

What will be the equilibrium concentration of [H2O]?

[H2O] =   M  

Part C

What will be the equilibrium concentration of [CO2]?

[CO2] =   M  

Part D

What will be the equilibrium concentration of [H2]?

[H2] =   M  

Explanation / Answer

CO(g) + H2O(g) CO2(g) + H2(g)
initial conc 0.140 0.140 0 0

change -c -c +c +c

Equb conc 0.140-c 0.140-c c c

Equilibrium constant , Kc = 102 = ( c x c) / ((0.140-c)(0.140-c))

c / ( 0.140-c) = 10

0.1c = 0.140-c

1.1c = 0.140

c = 0.127 M

Therefore the equilibrium concentration of CO = 0.140-c = 0.013 M

the equilibrium concentration of H2O = 0.140 - c = 0.013 M

the equilibrium concentration of CO2 = c = 0.127M

the equilibrium concentration of H2 = c = 0.127 M

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