Please check if the answers are right, and how do I do the third question findin
ID: 492877 • Letter: P
Question
Please check if the answers are right, and how do I do the third question finding delta H vap?
not simple answers 1. Why does equilibrium vapor pressure increase with temperature? Because as temperature inceau ser, moee water moeeceues on the surface y me liquid are capabwe g overcoming the in be motewa ces to the surmeendung warer moeeuues and wiw evenhus go into the vapor onase 2. The theoretical vap of hexane is 28.9 mol. Why is there such a difference between the value for hexane and the value for water? What forces are involved here? wales has Shan aipoee dipoee fences Chuprocen kandng and is ve Et takes a lot energy to pu u water a ham has no ear band. so takes less energy to beaak bandt and so ewa Rzades faster 3. Taking the following data, determine AHvap for 2-propanol. Attach Excel spreadsheet and graph and show work. Convert to k Convert to Temperature CC) Vapor Pressure (torr atm 32.42 7.0 92.47 25.0 225.1 45.0 334.4 55.0 482.9 65.0 at 213 220 k 32. u o.ou. Minn too tor 25 213 k 0.12 am 760 SS 1213 324 k 22s. 760 0.62 atm 760Explanation / Answer
Vapor pressure is defined as the equilibrium pressure at which the rate of vaporization equals the rate of condensation at the given temperature.
As the temperature is increased, the rate of vaporization increases and the rate of condensation also will have to increase. So increase in temperature results in more vapor and hence more vapor pressure.
2. Due to net work of hydrogen bonds present in water molecules, higher energy is required to take the liquid molecules of water to vapor state leading to high heat of vaporization. Hexane is non polar and requires less energy for breaking the liquid state to be taken to vapor state.
3. the relation between vapor pressure, (P in atm) and latent heat of vaporization (deltaHvap) are related as
lnP= -deltaHvap/RT +C, where C is integration constant. So a plot of 1/T vs lnP gives a straight line whose slope is deltaHvap/R
given vapor pressure data in mm Hg is converted to atm be dividing the vapor pressure with 760. The data is plotted and shown below
the slope is -deltaH/R = -4388
deltaH= 4388*8.314 J/mole.K= 36482 J/mole= 36.482 Kj/mole