An oil rig pumps 30. barrels of oil/day, exactly. Each barrel holds 55.0 gallons
ID: 493547 • Letter: A
Question
An oil rig pumps 30. barrels of oil/day, exactly. Each barrel holds 55.0 gallons. If the density of the crude oil is 2.35 g/mL how long will it take the rig to produce 5.00 times 10^5 kg of oil? A new lab technician, on his first day on the job, drops his lab key into a large bottle of concentrated nitric acid, and key begins to dissolve. The mass of the key is 2.03 oz and has a density of 6.347 g/cm^3. The acid dissolves the key at a rate of 0.00235 g/s. By the time the lab tech gets the key out of the acid, 10.0 minutes have passed. What is the volume of the key remaining? A snail escapes from a French restaurant on foot. The snail can crawl exactly one inch in exactly 5 seconds. It has to crawl 12.03 km to get to the open countryside. After exactly 12 days, how far is the snail from the countryside? 58.752 g of aluminum pellets were added to 24.52 mL of water in a graduated cylinder. The water level rises to 46.28 mL. Calculate the density of the aluminum pellets.Explanation / Answer
Ans. 8. Amount of oil pumped in 1 day = 30 barrels
= 30 x (55.0 gallons) = 1650 gallons ; [1 barrel = 55.0 gallons]
= 1650 x (3.785 L) = 6245.25 L ; [1 gallon = 3.875 L]
= 6245250 mL ; [1 L = 1000 mL]
= 6245250 mL x (2.35 g/ mL) ; [density is 2.35 g/ mL]
= 14676337.5 g
= 14676.3375 kg ; [1 kg = 1000 g]
Thus, oil pumping rate = 14676.3375 kg/ day
Now,
Time required to produce 5.00 x 105 kg oil = (5.00 x 105 kg) / oil pumping rate
(5.00 x 105 kg) / oil pumping rate
= (5.00 x 105 kg) / (14676.3375 kg/ day)
= 34.068 days
Ans. 9. Mass of key = 2.03 oz
= 2.03 x (28.38 g) ; [1 oz = 28.38 g]
= 65.274 g
Rate of dissolution = 0.00235 g/s
Total mass dissolved in in 10 minutes = dissolution rate x time of dissolution
= (0.00235 g/s) x 10 min
= (0.00235 g/s) x 10 x 60 s ; [1 min = 60 s]
= 1.41 g
Remaining mass = Initial mass – Dissolved mass
= 65.274 g – 1.41 g
= 63.864 g
Remaining volume of key = Remaining mass / density of key
= 63.864 g / (6.347 g/ cm3)
= 10.062 cm3
Ans. 10. Distance travelled by snail in 12 day = speed x time
= (1 inch / 5 s) x 12 day
= (2.54 inch/ 5s) x 12 day ; [1 inch = 2.54 cm]
= (2.54 cm/ 5s) x 12 x 86400s ; [1 day = 86400 s]
= 526694.4 cm
= 5266.944 m ; [1 m = 100 cm]
= 5.26 km ; [1 km = 1000 m]
Distance from the countryside =
(distance between restaurant and countryside)- (distance travelled)
= 12.03 km – 5.26 km
= 6.77 km
Ans. 11. Volume of Al = Increase in volume =
(Final water level – Initial water level)
= 46.28 mL – 24.52 mL = 21.76 mL
Mass of Al = 58.752 g
Density = Mass / Volume
= 58.752 g / 21.76 mL
= 2.76 g/ mL