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Maria WileyPLUS C Secure https:// edugen.wileypluss.com/ edugen/student/main WileyPLUS Felder, Rousseau, Bullard, Elementary Principles of Chemical Processes, 4e CHEMICAL FUNDAMENTALS (CHE 2171) Home Read, Study & Practice Assignment Gradebook Assignment open Assignment CALCULATOR FULL SCREEN PRINTER VERSION BACK NEXT ASSIGNMENT RESOURCES Problem 4.80 Methanol Synthesis Chapter 4with reactions Problem 4.52 Ace! L Your answer is partially correct. Try again Problem 4.53 Ammonia Methanol is synthesized from carbon monoxide and hydrogen in a catalytic reactor. The fresh feed to the process contains 32.0 mol% co, 64.0 mol% H2 and 4.00 mol% N2. This stream is mixed with a recycle stream in a ratio of 13.00 mol recycle/1 mo fresh feed to produce the feed to the reactor, which contains 12.0 mol% N2. Problem .65 Wate The reactor effluent goes to a condenser from which two streams emerge: a liquid product stream containing essentially all of the methanol formed in the reactor, and a gas stream containing all of the Co, H and N2 leaving the reactor. 2, The gas stream is split into two fractions; one is removed from the process as a purge stream, and the other is the recycle stream that combines with the fresh feed to the reactor. Production Problem 4.80 Meth For a methanol production rate of 100.0 mol/h, calculate the fresh feed rate (molh, the molar flow rate and composition of the purge gas, and the overall and single-pass conversions. Fresh feed rate T100 mol/h and Butane Mixture Review Score Purge rate 31.74 Review Results by Study ective mol fraction co in purge 0.2913 mol fraction N2 in purge To.126 overall co conversion 71,106 Single-pass co conversion 5.54 License Agreement Priva Policy I 2000-2017 John Wiley Son Inc. All Rights Reserved. A Division of 2ohn Wiley & Sons Inc. Version 4.22.2.9

Explanation / Answer

Start at mixing point

Feed 2x +x -0.013

X=0.29 mol

N2 balance       4+500 y= 0.13*600

                        Y=0.148 mol n2/mol

Recycle

Y+z+2z=1.0

3z=1-0.148

Z=0.248 mol/mol

OVERAL; SYSTEM ATOMIC BALANCE

C:32=N3 +(0.284)np

N2: 4 =(0.148)np                 np=27.0 mol/h --------------answer

---à n3=24.3 mol/h-------answer

Overall Conversion =243.3/32=0 .76

Single Conversion =243.3/(0.29)*600=0 .14

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