Heres what i have gathered from doingmy lab experiment. i need help doing with t
ID: 500289 • Letter: H
Question
Heres what i have gathered from doingmy lab experiment. i need help doing with the rest
i need help with the following below. if someone can do them for me. that would be greatly appreciated
take all relative rates as being equal to 1000/t. Fill in the following table, first calculating the relative reaction rate for each mixture. Time t (sec) Relative Rate Reactant Concentrations Reaction for Color of Reaction in Reacting Mixture (M) Temp. Mixture to Change 1000lt in Co [Bro, 0.0020 002 see 22.22 002 IS See e33 rooli The reactant concentrations in the reaction mixture are not those of the stock solutions, since the reagents were diluted by the other solutions. The final volume of the reaction mixture is 50 mL in all cases. Since the number of moles of reactant does not change on dilution we can say, for example, for IT ion, that no. moles I I- stock stock MI- mixture V mixtureExplanation / Answer
Slope = -6683.9
In this plot Ea/R = -6683.9
Ea = -6683.9 * 8.314 J/K/mol = 55569.9 J/mol
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In iodine clock reaction rate law is :
Rate = k [I-]^1[BrO3^-]^1[H+]^2
k = rate / [I-]^1[BrO3^-]^1[H+]^2
reaction 1. k = 6.993/(0.002)*(0.008)*(0.02)^2 = 1.09 *10^9
reaction 2 : k = 9.439/0.004*0.008 *(0.02)^2 = 7.37*10^8
reaction 3 : k = 13.89/0.002*0.016*(0.02) ^2 = 1.08*10^9
reaction 4 : k = 22.22/0.002 *0.008 *(0.04)^2 = 8.68 *10^8
average k = 0.94*10^9
The value of rate constant are nearly same because, rate constant does not change with concentration . It dpends on temperature.
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rate of reaction 5 = 0.94*10^9 * (0.0016)*(0.004)*(0.03)^2 = 5.414
time (predicted) = 1000/5.414 = 184.7 sec
time (observe) = 158 sec