Can someone explain the reasoning behind this please? 3. Nitric oxide reacts wit

Question

Can someone explain the reasoning behind this please?

3. Nitric oxide reacts with hydrogen gas at elevated temperatures, 2 NO(g) 2 H2(g) N2(g)+ H2O(g) It is found experimentally that if the concentration of H2 is reduced by a factor of 4, the rate of the reaction is also reduced by a factor of 4. And if the concentration of NO is increased by a factor of 5, the rate increases 25 fold. By what factor will the overall reaction rate change if the concentrations of both NO and H2 are doubled? (a) 2 (b) 4 (c) 8 (d) 10 (e) 16

Explanation / Answer

Rate = k*[NO]^x [H2]^y

if H2 is reduced by 4, then rate reduced by 4

so

y = 1, since it is linear, i.e. (4x)^1 = rate will increase by 4

for...

N,

if we increase by 5, there is an effect by 25 --> ln(25)/ln(5) = 2

so.

x = 2

the overall rate:

Rate = k*[NO]^2[H2]

find overall change if:

NO and H2 are doubled;

2^2 * 2^1 = 4*2 = 8

answer is 8x

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