A sample of a crystalline compound, when heated in an open test tube, produced s
ID: 501017 • Letter: A
Question
Explanation / Answer
2) When the hydrate is heated it tends to loose its water of hydration which appear as droplets in the cooler regions of the test tube. It is mentioned that the original hydrate forms a colorless solution when dissolved in water. Now, if the hydrate was a 'true hydrate' then the residue left in the test tube when once again dissolved in water should also form a colorless solution. Instead, it forms a yellowish brown solution, which indiactes that it is not a true hydrate.
3) General formula of a hydrate is: salt.XH2O
Here, X refers to the water of hydration. i.e the water present in these compounds as part of their crystalline structure.
4) Given hydrate: CoCl2. 6H2O
Mass of hydrate = 25 g
Mass of water = 11.3 g
% H2O = (mass of water/mass of hydrate)*100 = (11.3/25)*100 = 45.2%