In the combustion of propane (C_3H_8), if 200.0 g of propane is burned in air, h
ID: 513563 • Letter: I
Question
In the combustion of propane (C_3H_8), if 200.0 g of propane is burned in air, how many grams of water are produced? [326.8 g H_2O] 1.000 g of an organic molecule that contains only carbon and hydrogen burns completely in the presence of excess oxygen. It yields 0.0333 mol of CO_2 and 0.599 g of H_2O. Find the empirical mass of the compound. The molecular mass was determined experimentally to be 84.159 g/mol. What is the molecular formula? [C_6H_12] Balance these equations, and identify the type of reaction H2O(l) rightarrow H2(g) + O2(g) Zn(s) + Au(aq)^+ rightarrow Zn(aq)^2+ + Ag(s) Hydrochloric acid reacts with a solid chunk of aluminum to produce hydrogen gas and aluminum ions. Write the balanced chemical equation for this reaction. What type of reaction is this?Explanation / Answer
(4)
C3H8 (g) + 5 O2 ------------> 3 CO2 (g)+ 4 H2O (l)
From tha above balanced equation,
1 mol of propane produces 4 mol H2O
(OR) 44 g. of propane produces 72 g. of water
then,
200.0 g. of propane produces 200.0 * 72 / 44 = 327.3 g. of water.