I need question 3 answered Write the reaction for the dissociation of KHT(s) in
ID: 513838 • Letter: I
Question
I need question 3 answered Write the reaction for the dissociation of KHT(s) in water. Write the equilibrium expression for the dissociation of KHT in water. Develop an ICE Chart for the dissociation of KHT in water. During the Weak Acid Laboratory, you determined the HP concentration for the dissociation of KHT in water to be approximately 0.0387 M. Determine the K_sp for the dissociation of KHT in pure water. Why is it important to add enough KHT to the KCI-NaCl solution in this lab to ensure solid remains?Explanation / Answer
KHT =potassium hydrogen tartarate
K+ -OOC-(CH2O)2-COOH +H2O <---->K+ -OOC-(CH2O)2-COO- +H3O+
ICE
[ KOOC-(CH2O)2-COOH] [KOOC-(CH2O)2-COO-] [H3O+]
Initial 0.1M(say) 0 0
change -x +x +x
equilibrium 0.1M-x x x
for KHT ka1=1.0*10^-3
ka2=4.6*10^-5
ka2=[KOOC-(CH2O)2-COO-] [H3O+]/ [ KOOC-(CH2O)2-COOH] =x*x/0.1-x=x^2/0.1-x
ka2=4.6*10^-5=x^2/0.1-x