Please Answer #4 and show steps eA 445nm=18565.22 eA 615mn=0 eB 445nm=2521.74 eB
ID: 514403 • Letter: P
Question
Please Answer #4 and show steps
eA 445nm=18565.22
eA 615mn=0
eB 445nm=2521.74
eB 615mn=43695.65
Calculate [HIn] and [In^-] for your solutions by solving the pair of simultaneous equations by hand. Show your calculation for one of your unknown solutions below. Attach three spreadsheets to this report form showing the calculation of the pH of the unknown solutions assigned. Spreadsheets must be complete with Henderson-Hasselbalch equation results clearly labeled and results readily identified with text and appropriate boxes.Explanation / Answer
You have not specified what the subscripts A and B in the molar absorption coefficients refer to.
Assuming that A refers to the [HIn] state and B refers to the [In-] state.
The two linear equations that will be formed are:
A445 = eA(445)*l*[HIn] + eB(445)*l*[In-]
A615 = eA(615)*l*[HIn] + eB(615)*l*[In-]
Putting values into the above two equations we obtain the following two equations:
0.270 = 18565.22*1*[HIn] + 2521.74*1*[In-] ----(I)
0.509 = 0*1*[HIn] + 43695.65*1*[In-] ----(II)
Solving (I) and (II), we get:
[HIn] = 1.29*10-5 M
[In-] = 1.16*10-5 M