Consider the following reaction at constant pressure. Use the information here t

Question

Consider the following reaction at constant pressure. Use the information here to determine the value of delta S_surr at 298 K. Predict whether or not this reaction will be spontaneous at this temperature. N_2(g) + 2O_2(g) rightarrow 2NO_2(g) Delta_r H = +66.4 kJ Delta S_surr = -66.4 J K^-1 mol^-1, reaction is not spontaneous Delta S_surr = +66.4 kJ K^-1 mol^-1, reaction is not spontaneous Delta S_surr = +223 J K^-1 mol^-1, reaction is spontaneous Delta S_surr = -66.4 J K^-1 mol^-1, reaction is spontaneous Delta S_surr = -223 J K^-1 mol^_1, reaction is not spontaneous

Explanation / Answer

rH = 66.4 KJ = 66400 J

Reaction absorbs heat

So, surrounding must give heat

so, Qsurr = -66400 J/mol

T = 298 K

S Surr = Q surr / T

= -66400 J/mol / 298 K

= -223 J/mol.K

Answer: -223 J/mol.K

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