In yeast, ethanol is produced from glucose under anaerobic conditions. What is t

Question

In yeast, ethanol is produced from glucose under anaerobic conditions. What is the maximum amount of ethanol (in millimoles) that could theoretically be produced under the following conditions? A cell-free yeast extract is placed in a solution that contains 3.00 times 10^2 mmol glucose, 0.40 mmol ADP, 0.40 m P_i, 0.80 mmol ATP, 0.20 mmol NAD^+ and 0.20 mmol NADH. It is kept under anaerobic conditions. Number mmol Under the same conditions, what is the theoretical minimum amount of glucose (in mil moles) required in the solution form the maximum amount of ethanol? Number mmol

Explanation / Answer

glucose molecule is broken down into two pyruvate molecules in a process known as glycolysis.

C6H12O6 + 2 ADP + 2 Pi + 2 NAD+ ---> 2 CH3COCOO- + 2 ATP + 2 NADH + 2 H2O + 2 H+

Again this CH3COCOO- reacts to form ethanol according to the following reaction-

2 CH3COCOO- --->2CH3CHO + 2CO2

2CH3CHO + 2NADH ---> 2 C2H5OH

Combining all

C6H12O6 + 2 ADP + 2 Pi ---> 2 C2H5OH + 2 ATP + 2 CO2

1                 2               2             2

300             0.40        0.40         

limiting reagent is ADP and Pi

maximum amount of ethanol = 0.40 mmol

1mol glucse ---------------> 2mol ethanol

x mol glucose --------------> 0.40 mmol ethanol

x = 0.40 / 2 = 0.20

minimum mmol of glucose = 0.20

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---