In yeast, ethanol is produced from glucose under anaerobic conditions. What is t

Question

In yeast, ethanol is produced from glucose under anaerobic conditions. What is the maximum amount of ethanol (in millimoles) that could theoretically be produced under the following conditions? A cell-free yeast extract is placed in a solution that contains 325 mmol glucose, 0.30 mmol ADP, 0.30 mmol Pi, 0.60 mmol ATP, 0.20 mmol NAD, and 0.20 mmol NADH. It is kept under anaerobic conditions. Number 35 mmol Under the same conditions, what is the theoretical minimum amount of glucose (in millimoles) required in the solution to form the maximum amount of ethanol? Number .18 mmol

Explanation / Answer

According to the question;

As we know that;

A)

First, we will see the equation which states the production of ethanol from glucose

So, the equation is,

C6H12O6 + 2ADP + 2Pi---> 2C2H5OH + 2 ATP + 2 CO2

The above equation clearly states that

Then,

But if you want to know how ethanol production is carried out by the provided things,

Then,

We need to take a look at the below set of equations;

So,

C6H12O6 + 2 ADP + 2 Pi+ 2 NAD+ ---> 2 CH3COCOO- + 2 ATP + 2 NADH + 2 H2O + 2 H+

2 CH3COCOO- --->2CH3CHO + 2CO2

2CH3CHO + 2NADH ---> 2C2H5OH

Then,

Based on the above equation, we can say that 325 mmol of glucose will produce 650 mmol of ethanol, as one molecule of glucose is giving rise to 2 molecules of ethanol.

In the same way, 0.30 mmol of ADP will result in 0.30 mmol of Ethanol

And 0.30 mmol of pi will result in 0.30 mol of Ethanol

B)

From1 mole of glucose, We will get 2 moles of ethanol

So,

From 0.30 mmol of ethanol, we can get 0.15 mmol of glucose

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