Map a Sapling Learning macmillan learning wire Consider a galvanic (voltaic) cel

Question

Map a Sapling Learning macmillan learning wire Consider a galvanic (voltaic) cell that has the generic metals X and Y as electrodes. If X is more reactive than Y (that is, X more readily reacts to form a cation than Y does), classify the following descriptions by salt bridge Y whether they apply to the X or Y electrode X electrode Y electrode x2+ (aq) Y21 (aq) electrons in the cations from the salt loses mass wire flow toward bridge flow toward cathode gains mass anions from the salt anode bridge flow toward electrons in the wire flow away from Previous 3 Give Up & View Solution Check Answer Next Exit Hint

Explanation / Answer

The question mentions that X readily forms its divalent cation , so the events occuring under the label X electrode will be,

loses mass ( as X dissolves in electrolyte to form cations)

anode ( oxidation occurs at anode)

anions from the salt bridge flow toward (because the concentration of cations is increasing in the solution. So anions travel from high concentration to lower)

electrons in the wire flow away from ( as metal is getting oxidised , it liberates electrons)

now the events occuring under Y electrode will be

electrons in the wire flow toward ( as the metal is getting reduced)

cations from the salt bridge flow toward ( because the cation concentration is decreasing in the solution )

cathode ( reduction occurs )

gains mass ( due to metal deposition )

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