Combustion of hydrocarbons such as undecane (C_11 H_24) produces carbon dioxide,
ID: 517037 • Letter: C
Question
Combustion of hydrocarbons such as undecane (C_11 H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosphere can trap the sun's heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide. write a balanced chemical equation, including physical state symbols, for the combustion of liquid undecane into gaseous carbon dioxide and gaseous water. Suppose 0.420 kg of undecane are burned in air at a pressure of exactly l atm and a temperature of 13.0 degree C. Calculate the volume of carbon dioxide gas that is produced. Round your answer to 3 significant digits.Explanation / Answer
undecane is C11H24
its combustion is C11H24+ 17O2 -------->11CO2 + 12H2O ( this is the balanced equation)
molar mass of C11H24= 11*12+1*24= 156, moles of undecane in 0.420 kg ( i.ee 420 gm)= mass/molar mass = 420/156=2.69 gmoles
from the stoichiometry of the reaction, 1 mole of undecane gives 11 mole of CO2
2.69 moles gives 2.69*11= 29.6 gmoles
from gas law P=1atm T= 13 deg.c= 13+273= 286K, n= 29.6 gmoles. R =0.0821 L.atm/mole.K
V= nRT/P= 29.6*0.0821*286/1 =695 Liters of CO2