Combustion of hydrocarbons such as pentane (C_5H_12) produces carbon dioxide, a

Question

Combustion of hydrocarbons such as pentane (C_5H_12) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosphere can trap the Sun's heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide. Write a balanced chemical equation, including physical state symbols, for the combustion of liquid pentane into gaseous carbon dioxide and gaseous water. Suppose 0.350 kg of pentane are burned in air at a pressure of exactly 1 atm and a temperature of 20.0 degree C. Calculate the volume of carbon dioxide gas that is produced.Be sure your answer has the correct number of significant digits.

Explanation / Answer

Q1.

First, define the equation

C5H12 + O2 = CO2 + H2O

balance C, then, H, finally O

C5H12 + 8O2 = 5CO2 + 6H2O

add phases

C5H12(l) + 8O2(g) = 5CO2(g) + 6H2O(g)

Q2.

m = 0.350 kg = 350 g of pentane

mol of pentane = mass/MW = 350/72.15 = 4.8510 mol of pentane

now,

1 mol of pentane = 5 mol of CO2

4.8510 mol of pentane = 5*4.8510 = 24.255 mol of CO2 expected

now,

PV = nRT

V= nRT/P

substitute known data

V = (24.255)(0.082)(293)/1

V = 582.7 liters

2 sig fig = 580 Liters

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