Mass of gelatin capsule Mass of capsule and alloy Mass of empty beaker Mass of b

Question

Mass of gelatin capsule Mass of capsule and alloy Mass of empty beaker Mass of beaker and displaced water Barometric pressure Temperature of water Calculations Mass of alloy Mass of displaced water Volume of displaced water (see Appendix H) Volume of hydrogen gas (V Temperature of hydrogen gas to be equal to temperature of the water) Vapor pressure of water (PH o) (at temp. of Ha gas, see Appendix H) Pressure of dry hydrogen gas Moles of hydrogen gas (n Hydrogen Moles of hydrogen per g sample (n Hrdro %Al (use graph or Equation 12) ur calculations on the reverse side of the graph 0.112 g 0.271 g 141.209 g 307.712 g 745.9 mm Hg 21°C 15 g mm Hg mm Hg mol mol/gs

Explanation / Answer

a)

volume displaced of water -- > 166.84 mL

volume of H2 gas = Volume of water = 166.84 mL

b)

Temperature of H2 gas = T of water = 21°C

c)

find vapor pressure of water at 21 °C

P° = 18.7 mm Hg

d)

Ptotal = 745.9-18.7 = 727.2mm Hg

e)

moles of gas

PV = nRT

n = PV/(RT) = 727.2*0.16684/(62.4*294) = 0.006613 moles of H2

f)

mol per gram --> 0.006613 / 0.159 = 0.041591 mol / G

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