Mass of beaker plus CaCO 3 = 119.972g VolumeCa 2+ solution prepared = 250 mL Mas

Question

Mass of beaker plus CaCO3 = 119.972g          VolumeCa2+ solution prepared = 250 mL Mass of beaker less sample = 119.568g           Molarityof Ca2+ = _____________ Mass of CaCO3 sample=        0.404g              MolesCa2+ in each aliquot titrated = __________ Number of moles CaCO3 in Sample (formula mass =100.1)       ___________ Question: Please write out in full detail the steps tofigure out the blanks above as well as the answers to them. Thank you. Mass of beaker plus CaCO3 = 119.972g          VolumeCa2+ solution prepared = 250 mL Mass of beaker less sample = 119.568g           Molarityof Ca2+ = _____________ Mass of CaCO3 sample=        0.404g              MolesCa2+ in each aliquot titrated = __________ Number of moles CaCO3 in Sample (formula mass =100.1)       ___________ Question: Please write out in full detail the steps tofigure out the blanks above as well as the answers to them. Thank you.

Explanation / Answer

   Mass of beaker plus CaCO3 = 119.972g          VolumeCa2+ solution prepared = 250 mL Mass of beaker less sample = 119.568g           Molarityof Ca2+ = _____________     Moles of CaCO3 =119.568g / (100.1g/mol) = 1.1945mol        Molarity ofCa2+ = 1.1945mol / 250mL =4.778M Mass of CaCO3 sample=        0.404g              MolesCa2+ in each aliquot titrated = __________ Moles Ca2+ in each aliquot titrated =0.404g / (100.1g/mol) = 4.036mol
Mass of beaker plus CaCO3 = 119.972g          VolumeCa2+ solution prepared = 250 mL Mass of beaker less sample = 119.568g           Molarityof Ca2+ = _____________     Moles of CaCO3 =119.568g / (100.1g/mol) = 1.1945mol        Molarity ofCa2+ = 1.1945mol / 250mL =4.778M Mass of CaCO3 sample=        0.404g              MolesCa2+ in each aliquot titrated = __________ Moles Ca2+ in each aliquot titrated =0.404g / (100.1g/mol) = 4.036mol

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