Mass of NiCl_2 middot 6H_2O (obtaining using the TARE feature) = Appearance of s
ID: 492886 • Letter: M
Question
Mass of NiCl_2 middot 6H_2O (obtaining using the TARE feature) = Appearance of solid NiCl_2 middot 6H_2O Appearance of NiCl_2 middot 6H_2O solution mL, Volume of solution (en soln) = mL Concentration of en solution (From the label on the bottle) = mass percentage Density of EN solution (From Procedure Step 4) = g/mL Appearance of en solution before addition to the hydrate: Appearance of reaction mixture after addition of en solution to the hydrate: Appearance of reaction mixture after addition of acetone Color of product. Ni(en)_3Cl_2, after drying process: Mass of empty plastic bag (or vial) + product = g Mass of empty plastic bag (or vial) = g Mass of product (actual yield) = g To determine the molar mass of the reactants would you calculate it for H_2NCH_2CH_2NH_2 or for 3H_2NCH_2CH_2NH_2 What precautions must be taken knowing that Ni(en)_3Cl_3h is soluble in water? If you were to use a 32.5 percentage ethylenediamine solution and the density of the solution is 0.985 g/mL, what is the mass of the ethylenediamine in 3.4 mL of this solution? What is the function of the acetone in this experiment? What are the safety precautions in the use of acetone?Explanation / Answer
we should calculate molar mass for H2N CH2 CH2 NH2 and not for 3H2N CH2 CH2 NH2 as we have to calculate only for the compound not for the stoichometric ratio as first only will give mass for 1 mole of compound but the second one will give mass of 3 mole of compound
2) Knowing that the given compound is soluble in water we should place it in watch glass which is completely dry and we should not even spill even a single drop of solution when we are to use it in solution form as every drop will contain certain amount of given compound
3)Given density of solution = 0.985 g/ml
Volume of solution = 3.4 ml
Mass of solution = 0.985 g/ml * 3.4 ml = 3.349 g
given solution contains 32.5 % ethyl diamine so
Mass of ethyldiamine = mass of solution * 32.5 / 100 = 1.088 g Answer