Identify the element that has a ground state electronic configuration of [Ar]4s^
ID: 519661 • Letter: I
Question
Identify the element that has a ground state electronic configuration of [Ar]4s^2 3d^104 p^1. A) Al B) In C) Ga D) B How many unpaired electrons arc present in the ground state P atom? A) 0 B) 3 C) 1 D) 2 E) 4 How many unpaired electrons are present in the ground state greaterthanorequalto atom? A) 0 B) 3 C) 1 D) 2 E) 4 How many of the following elements have 1 unpaired electron in the ground state? B Al S Cl A) 1 B) 2 C) 3 D) 4 How many valence electrons does an atom of S have? A) 3 B) 1 C) 2 D) 4 E) 6Explanation / Answer
S has got 1 paried electrons, P has got 3 paired electrons, d 5 and f 7.
1.
Atomic no of Argon is 18 and hence total no of electrons in the given configuration is 18+2+10+1=31
So atomic no 31 refer to Ga. ( C is correct)
2. Electronic configuration of P ( whose atomic no is 15) is [Ne] 3S23P3. So since 3S is filled, there are 3 unpaied electrons ( B is correct)
3. Ge electronic configuration is [Ne] 3d10 4s2 4p2 . So there is 0 unpaired electron in Ge ( A is correct)
4. electronic configuration :B [He] 2s22p1, 1 electronns unpaired. Al is [Ne]3s23p1, 1 unpaired electron, S is [Ne]3s23p4, 2 unpaied electrons, Cl : [Ne]3S23P5, so 1 unpared electron. 3 of them got one unpaied electron ( C is correct)
5. S electronc configuratin is 1s22s22p63s23p4. Valence9 electrons refer to electrosn in the outermost orbit In case of S there are 6 valence electrons in the outer most orbit. ( E is correct)