Match the words and numbers to the appropriate blanks in the sentences below. Ma
ID: 521319 • Letter: M
Question
Match the words and numbers to the appropriate blanks in the sentences below. Make certain each sentence is complete before submitting your answer. Electrolysis experiment C is run to completion with the following parameters: The positive terminal is made of Ag, the negative terminal is made of Ag, the solution is AgNO_3, the current is set to 4 to 3.50 A, and the time is set to 8 min. The final mass of the positive terminal is, and the final mass of the negative terminal is. Thus, the total Ag of metal that is electroplated is, or mol. Electrolysis experiment D is run to completion with the following parameters: The positive terminal is made of Cu, the negative terminal is made of Cu, the solution is Cu(NO_3)_2, the current is set to 3.50 A, and the time is set to 8 min. The final mass of the positive terminal is, and the final mass of the negative terminal is. Thus, the total mass of Cu that is electroplated is, or mol. The ratio of change in moles between experiments C and D is equal to. This corresponds to an identical ratio between the two experiments' .Explanation / Answer
(1) At negative electrode (anode) oxidation reaction occurs and at positive electrode(cathode) reduction reaction occurs.
Oxidation reaction (at anode or -ve electrode) : Ag (s) ----------> Ag+ (aq.) + e
Reduction reaction (at cathode or +ve electrode) : Ag+ (aq.) + e ----------> Ag (s)
SO, The final mass of positive terminal is increased and negative terminal is decreased.
According Faraday's first law of electrolysis,
W = M c t / Z F
W = 108 * 3.50 * 8 * 60 / (1 * 96500)
W = 1.88 g.
So, the total Ag metal that is electroplated is 1.88 g. or 1.88 / 108 = 0.0174 mol
(2)
At negative electrode (anode) oxidation reaction occurs and at positive electrode(cathode) reduction reaction occurs.
Oxidation reaction (at anode or -ve electrode) : Cu (s) ----------> Cu2+ (aq.) + e
Reduction reaction (at cathode or +ve electrode) : Cu2+ (aq.) + e ----------> Cu (s)
SO, The final mass of positive terminal is increased and negative terminal is decreased.
According Faraday's first law of electrolysis,
W = M c t / Z F
W = 63.5 * 3.50 * 8 * 60 / (2 * 96500)
W = 0.55 g.
So, the total Cu metal that is electroplated is 0.55 g. or 0.55 / 63.5 = 0.0087 mol