I reached the top of a Mountain at 6:32 AM on the morning of July 1, 2003. The t
ID: 526783 • Letter: I
Question
I reached the top of a Mountain at 6:32 AM on the morning of July 1, 2003. The temperature was a brisk 33 F (0.6 C). I drank all the water in my plastic bottle, capped the bottle, and placed it inside my bag. I arrived back in Location X around 2 PM and the temperature was a balmy 88 F (31 C). When I removed the empty water bottle from my bag, it was deformed due to the higher atmospheric pressure in Location X. I determined that the volume of the bottle in Location X was 23% smaller than the volume of the same bottle on top of the Mountain. Assuming that the atmospheric pressure in Location X is 1 atm, calculate the atmospheric pressure on top of Mountain
Explanation / Answer
given Px= 1 atm. Vx= 0.23Y, Y = volume at mountain, Tx= 31 deg.c= 31+273=304K
at mountains P= ?, V=Y, T= 0.6 deg.c= 0.6+273=273.6 K
Px*Vx/Tx= PV/T
P= PxVx*T/VTx= 1* 0.23Y*273.6/(Y* 304)=0.207 atm