Hey, so this is the H-nmr of my product that was synthesized via Fischer esterif

Question

Hey, so this is the H-nmr of my product that was synthesized via Fischer esterification. So we started with an unkown alcohol and we have to identify this unknown. ( the possible alcohols are benzyl alcohol, isbutanol, 1-octanol, isobutanol, 1-pentanol, isopentanol and 1- butanol. I think that my unknown alcohol was 1-octanol. here's the H-nmr spectrum please tell me whether I'm right or wrong? with explanation .

05/02/17 (19:24) 10.5 10.0 9.5 9.0 8,5 8.0 7.5 7.0 6.5 6.0 5.5 5.0 4.5 s.0 3.5 3.0 2.5 2.0 1.5 1.0 0.5 0.0 -0.5 1.0 2.0 3200 3000 2200 2000 1800 1400 200 200 200 2.5

Explanation / Answer

Yes, the unknown alcohol is 1-octanol. From 1H-NMR, we understand:

CH3-(CH2)4-(CH2)2-CH2-OH

E D C A B

A = 4.00 ppm

B = 2.10 ppm

C = 1.35 ppm

D = 1.25 ppm

E = 0.88 ppm

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